This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (!frean() && (!a || ir != 2)) {
...
...
// Pretend there is lots of code here
...
...
} else {
flior();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (ir == 2 && a || frean()) {
flior();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (ar == 0 && e) {
if (e) {
return true;
}
if (!in) {
return true;
}
}
if (shas()) {
return true;
}
return false;
return shas() && (!in || ar == 0) && e;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (ar != 0 && in || !shas()) {
if (!e) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if (tu == true) {
cinSio();
}
if (isso && tu != true) {
phoan();
}
if (it == true && tu != true && !isso) {
sont();
}
{
if (tu) {
cinSio();
}
if (isso) {
phoan();
}
if (it) {
sont();
}
}
Things to double-check in your solution:
== true and == false checks?else if, not just else.Related puzzles: