This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if ((!de || ussSoun()) && e) {
...
...
// Pretend there is lots of code here
...
...
} else {
langse();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (!e || !ussSoun() && de) {
langse();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (bri != ia) {
return true;
}
if (cil) {
return true;
}
if (sefo) {
return true;
}
if (poc) {
return true;
}
return false;
return poc && sefo && cil && bri != ia;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!sefo || !poc) {
if (!cil) {
if (bri == ia) {
return false;
}
}
}
return true;
Simplify the following messy chain of conditionals:
if (enge != a) {
douMuluc();
}
if (no == le && enge == a) {
snoLiess();
} else if (ci != 3 && enge == a && no != le) {
hozill();
}
{
if (enge != a) {
douMuluc();
}
if (no == le) {
snoLiess();
}
if (ci != 3) {
hozill();
}
}
Things to double-check in your solution:
== true and == false checks?else if, not just else.Related puzzles: