Booleans and conditionals: Correct Solution


Part 1

This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!

if (ci && hioWhu() || !un) {
    ...
    ...
    // Pretend there is lots of code here
    ...
    ...
} else {
    xang();
}

Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.

Solution

if (un && (!hioWhu() || !ci)) {
    xang();
} else {
    ...
    ...
    // Pretend there is lots of code here
    ...
    ...
}

Things to double-check in your solution:


Part 2

Simplify the following conditional chain so that it is a single return statement.

if (ir) {
    if (me) {
        if (uale()) {
            return true;
        }
        if (!tei) {
            return true;
        }
    }
}
return false;

Solution

return !tei && uale() || me || ir;

Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.

Solution

if (tei) {
    if (!uale()) {
        return false;
    }
}
if (!me) {
    return false;
}
if (!ir) {
    return false;
}
return true;

Part 3

Simplify the following messy chain of conditionals:

if (casi == true) {
    idrad();
} else if (beh == 4 && casi != true) {
    onma();
}
if (la <= 4 && casi != true && beh != 4) {
    hosceu();
}

Solution

{
    if (casi) {
        idrad();
    }
    if (beh == 4) {
        onma();
    }
    if (la <= 4) {
        hosceu();
    }
}

Things to double-check in your solution:


Related puzzles: