This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (!spi && eseu() < 6 || ridda()) {
...
...
// Pretend there is lots of code here
...
...
} else {
hofid();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (!ridda() && (eseu() > 6 || spi)) {
hofid();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (glind() || niao) {
if (cisse()) {
return true;
}
if (meuo) {
return true;
}
}
return false;
return meuo && cisse() || glind() || niao;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!meuo) {
if (!cisse()) {
return false;
}
}
if (!glind()) {
return false;
}
if (!niao) {
return false;
}
return true;
Simplify the following messy chain of conditionals:
if (hu == 8) {
prasde();
} else if (er == 7 && hu != 8) {
eess();
} else if (hu != 8 && er != 7) {
ussol();
}
{
if (hu == 8) {
prasde();
}
if (er == 7) {
eess();
}
ussol();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: