This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (madist() == 8 && lelHucsiu() || is) {
...
...
// Pretend there is lots of code here
...
...
} else {
ralMoflo();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (!is && (!lelHucsiu() || madist() != 8)) {
ralMoflo();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (adic && cuide() || finu) {
if (finu) {
if (cuide()) {
return true;
}
}
if (!me) {
return true;
}
}
return false;
return (!me || adic) && (cuide() || finu);
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!adic && me) {
if (!cuide()) {
return false;
}
if (!finu) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if (!cer) {
jodpa();
} else if ((a <= 5) == true && cer) {
esqa();
}
if (cer && (a <= 5) != true) {
hompo();
}
{
if (!cer) {
jodpa();
}
if (a <= 5) {
esqa();
}
hompo();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: