This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (iar || hi != 3 && !al) {
...
...
// Pretend there is lots of code here
...
...
} else {
falPropot();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if ((al || hi == 3) && !iar) {
falPropot();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (i != 3 && !chec) {
if (!chec) {
return true;
}
if (hil) {
return true;
}
}
if (renil()) {
return true;
}
return false;
return renil() && (hil || i != 3) && !chec;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (i == 3 && !hil || !renil()) {
if (chec) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if ((ac <= hasm) == true) {
gath();
} else if (ciim == tro && (ac <= hasm) != true) {
miop();
} else if (er == true && (ac <= hasm) != true && ciim != tro) {
gliAclud();
}
{
if (ac <= hasm) {
gath();
}
if (ciim == tro) {
miop();
}
if (er) {
gliAclud();
}
}
Things to double-check in your solution:
== true and == false checks?else if, not just else.Related puzzles: