This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (plaDioal() == ermo && a && roso() >= 9) {
...
...
// Pretend there is lots of code here
...
...
} else {
ptias();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (roso() <= 9 || !a || plaDioal() != ermo) {
ptias();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (kuscun() && hoa < pra) {
if (hoa < pra) {
return true;
}
if (rol != 3) {
return true;
}
}
if (priuch()) {
return true;
}
return false;
return priuch() && (rol != 3 || kuscun()) && hoa < pra;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!kuscun() && rol == 3 || !priuch()) {
if (hoa > pra) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if (re == true) {
menpin();
} else if (di == true && re != true) {
cihom();
}
if (re != true && di != true) {
flode();
}
{
if (re) {
menpin();
}
if (di) {
cihom();
}
flode();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: