This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (!cuou && vual() == 0 && oprang()) {
...
...
// Pretend there is lots of code here
...
...
} else {
rorrat();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (!oprang() || vual() != 0 || cuou) {
rorrat();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (fes < juw || ou) {
if (a) {
return true;
}
if (fouc) {
return true;
}
}
return false;
return fouc && a || fes < juw || ou;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!fouc) {
if (!a) {
return false;
}
}
if (fes > juw) {
return false;
}
if (!ou) {
return false;
}
return true;
Simplify the following messy chain of conditionals:
if (pela == ad) {
gacDioi();
} else if (u <= 1 && pela != ad) {
epro();
} else if (pela != ad && u >= 1) {
notsit();
}
{
if (pela == ad) {
gacDioi();
}
if (u <= 1) {
epro();
}
notsit();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: