This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (bonuss() && (noing() || !ul)) {
...
...
// Pretend there is lots of code here
...
...
} else {
sipnel();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (ul && !noing() || !bonuss()) {
sipnel();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (prud) {
return true;
}
if (phuss() == presos()) {
return true;
}
if (ap == 2) {
return true;
}
if (ganing()) {
return true;
}
return false;
return ganing() && ap == 2 && phuss() == presos() && prud;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!ganing()) {
if (phuss() != presos() || ap != 2) {
if (!prud) {
return false;
}
}
}
return true;
Simplify the following messy chain of conditionals:
if (crec == true) {
fres();
} else if (hos == true && crec != true) {
stoHarpuc();
}
if (crec != true && hos != true) {
sason();
}
{
if (crec) {
fres();
}
if (hos) {
stoHarpuc();
}
sason();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: