This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (jixSaccer() && (gepStist() || shung())) {
...
...
// Pretend there is lots of code here
...
...
} else {
voosme();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (!shung() && !gepStist() || !jixSaccer()) {
voosme();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (stru() && we) {
if (we) {
return true;
}
if (tred) {
return true;
}
if (ophi) {
return true;
}
}
return false;
return (ophi && tred || stru()) && we;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!stru() && !tred || !ophi) {
if (!we) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if (ano == false) {
cimEsi();
}
if (flis == true && ano != false) {
oceKnas();
} else if (ano != false && flis != true) {
thespu();
}
{
if (!ano) {
cimEsi();
}
if (flis) {
oceKnas();
}
thespu();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: