This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (!cali && po != 8 || ousRungaf()) {
...
...
// Pretend there is lots of code here
...
...
} else {
doue();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (!ousRungaf() && (po == 8 || cali)) {
doue();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (enlilf() && ca || ced != 9) {
if (ciar()) {
return true;
}
}
return false;
return ciar() || enlilf() && (ca || ced != 9);
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!enlilf() && !ciar()) {
if (!ciar()) {
return false;
}
if (!ca) {
return false;
}
if (ced == 9) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if (pra != 0) {
phuhas();
} else if (i == true && pra == 0) {
gresur();
} else if (pra == 0 && i != true) {
treVeocs();
}
{
if (pra != 0) {
phuhas();
}
if (i) {
gresur();
}
treVeocs();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: