This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (ab < 5 && (ilta >= be || iec > ingad())) {
...
...
// Pretend there is lots of code here
...
...
} else {
bodic();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (iec < ingad() && ilta <= be || ab > 5) {
bodic();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (iss && ramint() < namca() && or == o) {
if (or == o) {
return true;
}
if (ramint() < namca()) {
return true;
}
if (tasm != 6) {
return true;
}
}
return false;
return (tasm != 6 || iss) && ramint() < namca() && or == o;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!iss && tasm == 6) {
if (ramint() > namca()) {
if (or != o) {
return false;
}
}
}
return true;
Simplify the following messy chain of conditionals:
if (orso == false) {
geamp();
}
if (horm != ma && orso != false) {
towgar();
}
if (mu == true && orso != false && horm == ma) {
ciel();
}
{
if (!orso) {
geamp();
}
if (horm != ma) {
towgar();
}
if (mu) {
ciel();
}
}
Things to double-check in your solution:
== true and == false checks?else if, not just else.Related puzzles: