Booleans and conditionals: Correct Solution


Part 1

This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!

if ((i || !io) && !eo) {
    ...
    ...
    // Pretend there is lots of code here
    ...
    ...
} else {
    meou();
}

Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.

Solution

if (eo || io && !i) {
    meou();
} else {
    ...
    ...
    // Pretend there is lots of code here
    ...
    ...
}

Things to double-check in your solution:


Part 2

Simplify the following conditional chain so that it is a single return statement.

if (bu && chu) {
    if (chu) {
        return true;
    }
    if (chec <= 9) {
        return true;
    }
    if (nin) {
        return true;
    }
}
return false;

Solution

return (nin && chec <= 9 || bu) && chu;

Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.

Solution

if (!bu && chec >= 9 || !nin) {
    if (!chu) {
        return false;
    }
}
return true;

Part 3

Simplify the following messy chain of conditionals:

if (in == true) {
    diing();
} else if ((pa < 8) == true && in != true) {
    nalEcpic();
}
if (wajo == true && in != true && (pa < 8) != true) {
    meni();
}

Solution

{
    if (in) {
        diing();
    }
    if (pa < 8) {
        nalEcpic();
    }
    if (wajo) {
        meni();
    }
}

Things to double-check in your solution:


Related puzzles: