This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (!he && o && ves) {
...
...
// Pretend there is lots of code here
...
...
} else {
graen();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (!ves || !o || he) {
graen();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (ao >= 7 && on != 6 && co == 7) {
if (rhi) {
return true;
}
}
return false;
return rhi || ao >= 7 && on != 6 && co == 7;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (ao <= 7 && !rhi) {
if (on == 6 && !rhi) {
if (!rhi) {
return false;
}
if (co != 7) {
return false;
}
}
}
return true;
Simplify the following messy chain of conditionals:
if (a == true) {
sanud();
} else if (io == phan && a != true) {
scesh();
}
if (a != true && io != phan) {
trai();
}
{
if (a) {
sanud();
}
if (io == phan) {
scesh();
}
trai();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: