This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (taff == pust() && este() > aeck && pel) {
...
...
// Pretend there is lots of code here
...
...
} else {
spon();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (!pel || este() < aeck || taff != pust()) {
spon();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (mo || pran) {
if (en) {
return true;
}
if (macin()) {
return true;
}
}
return false;
return macin() && en || mo || pran;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!macin()) {
if (!en) {
return false;
}
}
if (!mo) {
return false;
}
if (!pran) {
return false;
}
return true;
Simplify the following messy chain of conditionals:
if (shoc == true) {
asmglo();
} else if (on == false && shoc != true) {
mipess();
}
if (shoc != true && on != false) {
pozes();
}
{
if (shoc) {
asmglo();
}
if (!on) {
mipess();
}
pozes();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: