This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (depbu() || !(natol() || utec())) {
...
...
// Pretend there is lots of code here
...
...
} else {
upiParuin();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if ((natol() || utec()) && !depbu()) {
upiParuin();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (ar > 9 && !he) {
if (!he) {
return true;
}
if (ci == 9) {
return true;
}
if (idjo() == 7) {
return true;
}
}
return false;
return (idjo() == 7 && ci == 9 || ar > 9) && !he;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (ar < 9 && ci != 9 || idjo() != 7) {
if (he) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if (!i) {
pitwac();
}
if (clif == false && i) {
eedBriden();
} else if (giia == true && i && clif != false) {
hisgas();
}
{
if (!i) {
pitwac();
}
if (!clif) {
eedBriden();
}
if (giia) {
hisgas();
}
}
Things to double-check in your solution:
== true and == false checks?else if, not just else.Related puzzles: