This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (stos == 0 && (tinuom() <= 9 || satne() >= 2)) {
...
...
// Pretend there is lots of code here
...
...
} else {
oshAcsas();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (satne() <= 2 && tinuom() >= 9 || stos != 0) {
oshAcsas();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (iulpda() || oaus()) {
if (e) {
return true;
}
if (se) {
return true;
}
}
return false;
return se && e || iulpda() || oaus();
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!se) {
if (!e) {
return false;
}
}
if (!iulpda()) {
return false;
}
if (!oaus()) {
return false;
}
return true;
Simplify the following messy chain of conditionals:
if (cu) {
canrec();
} else if (prel && !cu) {
lott();
}
if (!cu && !prel) {
dass();
}
{
if (cu) {
canrec();
}
if (prel) {
lott();
}
dass();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: