This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (ste && surph() > 4) {
...
...
// Pretend there is lots of code here
...
...
} else {
posm();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (surph() < 4 || !ste) {
posm();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (ierGriil()) {
if (ra != ient()) {
return true;
}
}
if (flitar() >= prul()) {
return true;
}
return false;
return flitar() >= prul() && (ra != ient() || ierGriil());
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (flitar() <= prul()) {
if (ra == ient()) {
return false;
}
if (!ierGriil()) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if (acs == true) {
zinLol();
}
if (!lu && acs != true) {
famar();
}
{
if (acs) {
zinLol();
}
if (!lu) {
famar();
}
}
Things to double-check in your solution:
== true and == false checks?else if, not just else.Related puzzles: