This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (cerBantte() || enmio() >= 0) {
...
...
// Pretend there is lots of code here
...
...
} else {
prid();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (enmio() <= 0 && !cerBantte()) {
prid();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (en) {
if (!o) {
if (eska) {
return true;
}
}
}
return false;
return eska || !o || en;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!eska) {
return false;
}
if (o) {
return false;
}
if (!en) {
return false;
}
return true;
Simplify the following messy chain of conditionals:
if (im == true) {
wanmit();
}
if (lu == true && im != true) {
ridal();
}
{
if (im) {
wanmit();
}
if (lu) {
ridal();
}
}
Things to double-check in your solution:
== true and == false checks?else if, not just else.Related puzzles: