This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (anegn() && !pebra()) {
...
...
// Pretend there is lots of code here
...
...
} else {
cheri();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (pebra() || !anegn()) {
cheri();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (enge) {
if (!eix) {
return true;
}
}
if (emeng()) {
return true;
}
return false;
return emeng() && (!eix || enge);
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!emeng()) {
if (eix) {
return false;
}
if (!enge) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if (le == false) {
phosud();
}
if (le != false) {
cesan();
}
{
if (!le) {
phosud();
}
cesan();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: