This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (!piur || houu() != zeges()) {
...
...
// Pretend there is lots of code here
...
...
} else {
rerJorn();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (houu() == zeges() && piur) {
rerJorn();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (ot || ehaSongpe()) {
if (ecul()) {
return true;
}
}
return false;
return ecul() || ot || ehaSongpe();
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!ecul()) {
return false;
}
if (!ot) {
return false;
}
if (!ehaSongpe()) {
return false;
}
return true;
Simplify the following messy chain of conditionals:
if ((a == ic) == true) {
pongs();
} else if (el < 2 && (a == ic) != true) {
bidu();
}
{
if (a == ic) {
pongs();
}
if (el < 2) {
bidu();
}
}
Things to double-check in your solution:
== true and == false checks?else if, not just else.Related puzzles: