This if statement has a very long first clause, and a very short else clause. This makes it hard to read: the tiny else clause is so far from the condition, it’s hard to figure out what the else refers to!
if (damben() == apec || !spedma()) {
...
...
// Pretend there is lots of code here
...
...
} else {
macso();
}
Improve readability by refactoring this conditional so that its two clauses are swapped: what is now the second clause (the else clause) comes first, and the first clause comes second.
if (spedma() && damben() != apec) {
macso();
} else {
...
...
// Pretend there is lots of code here
...
...
}
Things to double-check in your solution:
!(...) Instead, make sure you negate the condition by changing each part of it.Pretend there is lots of code here when you write out your solution! Just draw three dots; that’s enough.Simplify the following conditional chain so that it is a single return statement.
if (ul != 6) {
return true;
}
if (as) {
return true;
}
if (ponbi() == 2) {
return true;
}
return false;
return ponbi() == 2 && as && ul != 6;
Bonus challenge: rewrite the if/else chain above so that instead of consisting of many return true; statements with one return false; at the end, it has many return false; statements with one return true; at the end.
if (!as || ponbi() != 2) {
if (ul == 6) {
return false;
}
}
return true;
Simplify the following messy chain of conditionals:
if (mish == true) {
ptapec();
}
if (mish != true) {
thel();
}
{
if (mish) {
ptapec();
}
thel();
}
Things to double-check in your solution:
== true and == false checks?else, no final if.Related puzzles: