Translate the following loop into a for-each loop:
List<Bidxi> luns; ...
for (int n = 0; n < luns.size(); n++) {
risSpifer(luns.get(n), 7, -1);
rissia();
smahe();
luns.get(n).ouco(ceror);
}
for (Bidxi lun : luns) {
lun.get(i).ouco(ceror);
smahe();
rissia();
risSpifer(lun.get(i), 7, -1);
}
It is OK if you gave the variable for the individual collection element (lun) a different name, such as elem. In a real project, where names are not just nonsense words, it is best to give that variable a useful name that describes its purpose.
Translate the following natural language description of a loop into a for loop:
Declare a variable namedleof typelong, initialized toie. Then, untilleis not equal tocoor, decrementle.
for (long le = ie; le != coor; le--) {
...
}
Something to double-check in your solution:
le != coor)?Related puzzles: