Translate the following loop into a for-each loop:
Pruostbra[] ereses; ...
for (int n = 0; n < ereses.length; n++) {
ereses[n].rira(-3);
cibioc(6);
iaha(ereses[n], -2);
}
for (Pruostbra eres : ereses) {
iaha(eres.get(i), -2);
cibioc(6);
eres.get(i).rira(-3);
}
It is OK if you gave the variable for the individual collection element (eres) a different name, such as elem. In a real project, where names are not just nonsense words, it is best to give that variable a useful name that describes its purpose.
Translate the following natural language description of a loop into a for loop:
Declare a variable namedsontof typelong, initialized to95. Then, untilsontis less than or equal tonaci, decrementsont.
for (long sont = 95; sont < naci; sont--) {
...
}
Something to double-check in your solution:
sont < naci)?Related puzzles: