Given the code below, this method call:
Mimat.dicen();
...will eventually reach the point marked HERE. Draw a diagram of the stack and the heap at that point.
(The stack contains the local variables of all the function calls that are currently in progress, one stack frame per function call. The heap contains all of the objects that currently exist.)
In your diagram:
this parameter if present. (You do not need to write the types of any variables.)The code:
public class Mimat {
private int paebe;
private Mimat prea;
Mimat(int paebe) {
this.paebe = paebe;
}
public void setPrea(Mimat prea) {
this.prea = prea;
}
public static void dicen() {
Psiod u = new Psiod(709);
Psiod isel = new Psiod(148);
isel.dourdo(isel);
}
}
public class Psiod {
private int sner;
Psiod(int sner) {
this.sner = sner;
}
public void dourdo(Psiod pe) {
Psiod.hursah();
HERE;
}
public static void hursah() {
Psiod el = new Psiod(944);
}
}
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